Write the equation of gravitational acceleration which is used for any height $h$ from the surface of the Earth.
(N/A) The gravitational acceleration $g$ at a height $h$ above the surface of the Earth is given by the formula:
$g_h = g \left( \frac{R_e}{R_e + h} \right)^2$
Where:
$g_h$ is the acceleration due to gravity at height $h$.
$g$ is the acceleration due to gravity at the Earth's surface $(g \approx 9.8 \ m/s^2)$.
$R_e$ is the radius of the Earth.
$h$ is the height above the Earth's surface.
$g_h = g \left( \frac{R_e}{R_e + h} \right)^2$
Where:
$g_h$ is the acceleration due to gravity at height $h$.
$g$ is the acceleration due to gravity at the Earth's surface $(g \approx 9.8 \ m/s^2)$.
$R_e$ is the radius of the Earth.
$h$ is the height above the Earth's surface.
Explore More
Similar Questions
Weight of a body is maximum at
Easy
View SolutionAcceleration due to gravity at the surface of a planet is equal to that at the surface of the Earth,and its density is $1.5$ times that of the Earth. If the radius of the Earth is $R$,the radius of the planet is:
Medium
View SolutionThe mass and the diameter of a planet are three times the respective values for the Earth. The period of oscillation of a simple pendulum on the Earth is $2 \ s$. The period of oscillation of the same pendulum on the planet would be
DifficultJEE MAIN 2019
View SolutionChoose the correct alternative:
$(a)$ Acceleration due to gravity increases/decreases with increasing altitude.
$(b)$ Acceleration due to gravity increases/decreases with increasing depth (assume the Earth to be a sphere of uniform density).
$(c)$ Acceleration due to gravity is independent of mass of the Earth/mass of the body.
$(d)$ The formula $-G M m(1 / r_{2}-1 / r_{1})$ is more/less accurate than the formula $m g(r_{2}-r_{1})$ for the difference of potential energy between two points $r_{2}$ and $r_{1}$ distance away from the centre of the Earth.
$(a)$ Acceleration due to gravity increases/decreases with increasing altitude.
$(b)$ Acceleration due to gravity increases/decreases with increasing depth (assume the Earth to be a sphere of uniform density).
$(c)$ Acceleration due to gravity is independent of mass of the Earth/mass of the body.
$(d)$ The formula $-G M m(1 / r_{2}-1 / r_{1})$ is more/less accurate than the formula $m g(r_{2}-r_{1})$ for the difference of potential energy between two points $r_{2}$ and $r_{1}$ distance away from the centre of the Earth.
Medium
View SolutionIf the radius of earth shrinks by $2 \%$ while its mass remains the same,the acceleration due to gravity on the earth's surface will approximately:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo